American Gold Eagle (1/10 oz) melt value
United States, 1986–present. Contains 0.1 troy oz of pure gold. The value below updates with the live spot price.
Specifications
| Country | United States |
|---|---|
| Years | 1986–present |
| Composition | 91.67% gold, 3% silver, 5.33% copper |
| Total weight | 3.393 g |
| Purity | .9167 (91.67% gold) |
| Pure gold | 3.110 g (0.1 troy oz) |
| Diameter | 16.5 mm |
| Edge | Reeded |
| Obverse design | Augustus Saint-Gaudens |
| Reverse design | Miley Busiek (1986–2021), Jennie Norris (2021–present) |
| Face value | $5.00 |
Specifications: U.S. Mint specifications and U.S. coinage law.
Common questions
How much gold is in a American Gold Eagle (1/10 oz)?
A American Gold Eagle (1/10 oz) contains 0.1 troy ounces (3.110 grams) of pure gold. It weighs 3.393 grams in total and is .9167 fine.
How is the melt value of a American Gold Eagle (1/10 oz) calculated?
Multiply the pure gold content (0.1 troy oz) by the current gold spot price. The calculator on this page does this automatically with live prices.
What will a dealer pay for a American Gold Eagle (1/10 oz)?
Bullion coins and bars are usually bought close to the spot value of their metal content, while dealers sell them at a premium over spot. Ask any buyer what percent of melt they are paying and compare.
Related melt values
Melt value is an estimate of metal content at spot price. It is not an offer, appraisal or measure of collector value.