Liberty Head $10 Eagle melt value
United States, 1838–1907. Contains 0.48375 troy oz of pure gold. The value below updates with the live spot price.
Specifications
| Country | United States |
|---|---|
| Years | 1838–1907 |
| Denomination | $10 |
| Composition | 90% gold, 10% copper |
| Total weight | 16.718 g |
| Purity | .900 (90% gold) |
| Pure gold | 15.046 g (0.48375 troy oz) |
| Diameter | 27 mm |
| Edge | Reeded |
| Obverse design | Christian Gobrecht |
| Reverse design | Christian Gobrecht |
| Face value | $10.00 |
Specifications: U.S. Mint records and Smithsonian National Numismatic Collection.
Common questions
How much gold is in a Liberty Head $10 Eagle?
A Liberty Head $10 Eagle contains 0.48375 troy ounces (15.046 grams) of pure gold. It weighs 16.718 grams in total and is .900 fine.
How is the melt value of a Liberty Head $10 Eagle calculated?
Multiply the pure gold content (0.48375 troy oz) by the current gold spot price. The calculator on this page does this automatically with live prices.
Is a Liberty Head $10 Eagle worth more than melt value?
Often, yes. Scarce dates, certain mint marks and coins in high grade sell to collectors for more than their metal content. Common circulated examples usually trade close to melt. Check the date and mint mark before selling.
Related melt values
Melt value is an estimate of metal content at spot price. It is not an offer, appraisal or measure of collector value.